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Subject: RE: [xsl] xsl- Transforming to HTML table with two entries in each row From: Jarno.Elovirta@xxxxxxxxx Date: Fri, 7 Mar 2003 09:17:26 +0200 |
Hip hei!
> Let's say I hae the following XML
> <fields>
> <field>
> <name>Field 1</name>
> <value>Value 1</value>
> </field>
> <field>
> <name>Field 2</name>
> <value>Value 2</value>
> </field>
> <field>
> <name>Field 3</name>
> <value>Value 3</value>
> </field>
> <field>
> <name>Field 4</name>
> <value>Value 4</value>
> </field>
> </fields>
> and I want the html table output (using XSL transfomration) to be :
> <table>
> <tr>
> <td>Field 1</td>
> <td>Value 1</td>
> <td>Field 2</td>
> <td>Value 2</td>
> </tr>
> <tr>
> <td>Field 3</td>
> <td>Value 3</td>
> <td>Field 4</td>
> <td>Value 4</td>
> </tr>
> </table>
>
> My problem is creating the mechnism that puts 2 (istead of 1 which is
> simple and easy) "fields" in one row (tr element)
It's a grouping problem, and there's most probably an entry for it in the FAQ. Anyhow,
<xsl:template match="fields">
<table>
<xsl:for-each select="field[position() mod 2 = 1]">
<tr>
<xsl:for-each select="./* | following-sibling::field[1]/* ">
<td>
<xsl:value-of select="." />
</td>
</xsl:for-each>
</tr>
</xsl:for-each>
</table>
</xsl:template>
should do the trick.
Cheers,
Jarno - Delerium: Heaven's Earth (Matt Darey remix)
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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