Re: [xsl] bug in LibXSLT???

[S Woodside <sbwoodside@xxxxxxxxx>]

Not quite but this works:

    <xsl:for-each select="ancestor-or-self::*[@name]">
      <xsl:text>/</xsl:text>
      <xsl:value-of select="@name"/>
    </xsl:for-each>

(there's ancestors without a @name)

thanks.

simon

On Friday, March 7, 2003, at 04:45  AM, Jre@xxxxxxxxxxxx wrote:

> This is a problem with the line
>         <xsl:for-each select="ancestor-or-self::*/@name">
> If you change this to
>         <xsl:for-each select="ancestor-or-self::*">
> and then change
>         <xsl:value-of select="."/>
> to
>         <xsl:value-of select="@name"/>
> you'll get the ordering you want (and expect!).
>
> Daniel: I've logged this in bugzilla: 107804 (but you probably already
> know that by now).
>
> John Escott.
>
>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
--
www.simonwoodside.com -- 99% Devil, 1% Angel


XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list