Subject: RE: [xsl] Get Position of Node in Ancestor Context From: "Michael Kay" <mhk@xxxxxxxxx> Date: Mon, 10 Mar 2003 20:07:03 -0000 |
You are following the well-trodden mistake of thinking "I want the position of something, therefore I need the position() function". The position() function gives you the position of a node in the list of nodes you are currenly processing. If you want the position of a node relative to related nodes in the same tree, there are two ways of doing it: xsl:number, and count(). For example, count(preceding::*). In this example, xsl:number is a better bet. Michael Kay Software AG home: Michael.H.Kay@xxxxxxxxxxxx work: Michael.Kay@xxxxxxxxxxxxxx > -----Original Message----- > From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx > [mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx] On Behalf Of > Ted Stresen-Reuter > Sent: 10 March 2003 15:21 > To: XSL-List@xxxxxxxxxxxxxxxxxxxxxx > Subject: [xsl] Get Position of Node in Ancestor Context > > > Hi, > > I'm trying to get the position of the current node in the > context of an > ancestor. > > For example, I have a form element that has a number of children > elements, including non-form elements (such as P and DIV > elements). I'm > trying to retrieve the position of an INPUT element relative to the > parent FORM element, but not taking into account any non-form > elements > (such as P and DIV elements). > > Currently I have a template that matches "input | select | textarea" > but because they occur in the context of a TD element, position() > returns "1". I've tried using <xsl:value-of > select="ancestor::form/*/*[position()]" />, but this just isn't doing > the trick. > > Any suggestions how I can get the position of the current element > relative to a parent form element? > > Ted Stresen-Reuter > > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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