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Subject: AW: [xsl] Getting the value of the tag itself. From: Delaney Robin <Robin.Delaney@xxxxxxx> Date: Thu, 20 Mar 2003 16:30:27 +0100 |
<xsl:value-of select="name()"/>
- Robin
Robin Delaney
FJA Feilmeier & Junker GmbH
Elsenheimerstraße 65, 80687 München.
* +49 (0) 89 - 76 901-7058
Fax +49 (0) 89 - 76 901-9502
web http://www.fja.com
* Mailto:Robin.Delaney@xxxxxxx
> -----Ursprüngliche Nachricht-----
> Von: Simon Kelly [SMTP:kelly@xxxxxxxxxx]
> Gesendet am: Donnerstag, 20. März 2003 16:08
> An: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Betreff: [xsl] Getting the value of the tag itself.
>
> Hi all,
>
> I know haow to get all the relevent information from a node, but I am
> struggling to remeber how to get the nodes name itself. IE if I have a
> node
> called <table name="table1"> how do I print out it's name table, and not
> the
> @name table1??
>
> Cheers
>
> Simon
>
>
>
> Institut fuer
> Prozessdatenverarbeitung
> und Elektronik,
> Forschungszentrum Karlsruhe GmbH,
> Postfach 3640,
> D-76021 Karlsruhe,
> Germany.
>
> Tel: (+49)/7247 82-4042
> E-mail : kelly@xxxxxxxxxx
>
>
> XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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