Subject: AW: [xsl] Getting the value of the tag itself. From: Delaney Robin <Robin.Delaney@xxxxxxx> Date: Thu, 20 Mar 2003 16:30:27 +0100 |
<xsl:value-of select="name()"/> - Robin Robin Delaney FJA Feilmeier & Junker GmbH Elsenheimerstraße 65, 80687 München. * +49 (0) 89 - 76 901-7058 Fax +49 (0) 89 - 76 901-9502 web http://www.fja.com * Mailto:Robin.Delaney@xxxxxxx > -----Ursprüngliche Nachricht----- > Von: Simon Kelly [SMTP:kelly@xxxxxxxxxx] > Gesendet am: Donnerstag, 20. März 2003 16:08 > An: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > Betreff: [xsl] Getting the value of the tag itself. > > Hi all, > > I know haow to get all the relevent information from a node, but I am > struggling to remeber how to get the nodes name itself. IE if I have a > node > called <table name="table1"> how do I print out it's name table, and not > the > @name table1?? > > Cheers > > Simon > > > > Institut fuer > Prozessdatenverarbeitung > und Elektronik, > Forschungszentrum Karlsruhe GmbH, > Postfach 3640, > D-76021 Karlsruhe, > Germany. > > Tel: (+49)/7247 82-4042 > E-mail : kelly@xxxxxxxxxx > > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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