Re: [xsl] how to insert the *complete* content of a node

[Jeni Tennison <jeni@xxxxxxxxxxxxxxxx>]

Hi Danilo,

> Actually I do concern about attributes, so the proposed solution did
> not fit at all with what I need (but thanks a lot anyway!!) So I'm
> still trying with some other solution.
>
> Ah the:
> <xsl:template match="mytag">
>   <xsl:copy>
>     <xsl:copy-of select="*|@*"/>
>   </xsl:copy>
> </xsl:template>
>
> Still does not work. 
> I Do not want to print the outer tag (mytag in the example)

Then don't copy it (you're copying it with <xsl:copy> at the moment).

Note that in the above you're only copying *element* children of the
<mytag> element, but you've said that you want to get the *text*node*
children as well. In that case, the following might be more suitable:

<xsl:template match="mytag">
  <xsl:copy-of select="node()" />
</xsl:template>

I'm not sure what you want to do about the attributes. If you have:

  <mytag attr1="aaa">blabla <foo>some text</foo> blabla</mytag>

what do you want to generate?

Cheers,

Jeni

---
Jeni Tennison
http://www.jenitennison.com/


 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list