Subject: Re: [xsl] generate full xpath name to an attribute? From: Oleg Tkachenko <olegt@xxxxxxxxxxxxx> Date: Mon, 31 Mar 2003 14:57:47 +0200 |
hi, i need to generate the full xpath name (location) for attributes in the following xsl (see below).
instead of using <xsl:attribute name="name"><xsl:value-of select="name()"/></xsl:attribute> which gets me the just the attribute (field) name, i would like to generate the full xpath expression from the root of the document (i guess it would look something like: /......./Node/SingleForces@attribute_name). i.e. what do i use in instead of: <xsl:value-of select="name()"/> to get the fully qualified name for this field from the root.
See faq: http://www.dpawson.co.uk/xsl/sect2/N6077.html -- Oleg Tkachenko http://www.tkachenko.com/blog Multiconn Technologies, Israel
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