Subject: Re: [xsl] generate full xpath name to an attribute? From: David Carlisle <davidc@xxxxxxxxx> Date: Tue, 1 Apr 2003 09:36:05 +0100 |
yes and tried doing that with if's. i found some stuff in the archives about determining whether something is an element or an attribute at http://www.biglist.com/lists/xsl-list/archives/200212/msg00523.html and http://www.biglist.com/lists/xsl-list/archives/200212/msg00518.html <xsl:if test="../@*/."> <xsl:if test="../@*"> count(. | ../@*) = count(../@*) none of these seem to work very well. It's not surprising they don't work, if you read the messages you quoted you'd see that they are replies explaining that the suggested code was wrong. test="../@*/." is the same as test="../@*" and tests to see if your parent has any attributes. Ieven if you were using correct code to distinguish elements from attributes (eg self::* is true for elements and false for attributes) <xsl:if test="../@*/."> <xsl:text>@</xsl:text> </xsl:if> <xsl:if test="not(../@*/.)"> <xsl:text>/</xsl:text> </xsl:if> would be the wrong thing to do as even for attributes you need a / between steps, so that should not be conditional, the only conditional part needs to be whether to use a @ on the last step. But several full solutions to this problem are in the archives and the faq. David ________________________________________________________________________ This e-mail has been scanned for all viruses by Star Internet. The service is powered by MessageLabs. For more information on a proactive anti-virus service working around the clock, around the globe, visit: http://www.star.net.uk ________________________________________________________________________ XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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