[xsl] Parameterized sort

["Kim Tran" <tav1210@xxxxxxxxxxx>]

I have the following sort problem where I want to have the sort key defined 
as a parameter.

For example, here is my XML:
<document>
<row><column name="FirstName">John</column>
     <column name="LastName">Doo</column>
</row>
<row><column name="FirstName">Alice</column>
     <column name="LastName">Mulcaster</column>
</row>

I want to sort the list by either FirstName or LastName.  Here is my xsl 
file:

<?xml version="1.0" encoding="ISO-8859-1"?>
<xsl:stylesheet
 xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
 version="1.0" xmlns:xalan="http://xml.apache.org/xalan";>
<xsl:output method="xml"/>

<xsl:param name="sortByColumn" select="'FirstName'"/>
<xsl:template match="/">
<Document>
<xsl:for-each select="Document/row">
<xsl:sort select="column[@name=*[name()=$sortByColumn]]"/>
<row>
 <xsl:apply-templates select="column"/>
</row>
</xsl:for-each>
</Document>
</xsl:template>

<xsl:template match="column">
<xsl:copy-of select="."/>
</xsl:template>
</xsl:stylesheet>

However, it still doesn't work.  I know that the sort key if defined as 
parameter, I should use "xalan:evalue($sortKey)" or "*[name() = $sortKey]".  
In this case, I want to sort the rows by the FirstName column or by LastName 
column and First Name.

If I say,
<xsl:sort select="column[@name='FirstName']"/>
then, it works properly.

Many thanks in advance.





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