Subject: Re: [xsl] concatenated key From: "I-Lin Kuo" <ikuoikuo@xxxxxxxxxxx> Date: Wed, 23 Apr 2003 01:39:35 +0000 |
I don't think this can be solved with XSLT 1.0 and arbitrary numbers of children. If you can assert a fixed and preferably low maximum number of children, you can try use="concat(name(*[1]),'#',name(*[2]),name(*[3]))" etc. The # characters prevent spurious matches.
I-Lin Kuo, Ann Arbor, MI Macromedia Certified ColdFusion 5.0 Advanced Developer Sun Certified Java 2 Programmer Ann Arbor Java Users Group (http://www.aajug.org)
----Original Message Follows---- From: "J.Pietschmann" <j3322ptm@xxxxxxxx> Reply-To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: Re: [xsl] concatenated key Date: Wed, 23 Apr 2003 00:43:15 +0200
Given a node, I'm trying to identify/pull out those nodes in the document having the same set of identically named child nodes....
The way I'm thinking about doing this is to construct an xsl:key where the value of the key consists of a concatenation of all the @name of its children and then do a select on the key. However, I can't figure out what expression I should have for the use="" attribute of xsl:key, and
I don't think this can be solved with XSLT 1.0 and arbitrary numbers of children. If you can assert a fixed and preferably low maximum number of children, you can try use="concat(name(*[1]),'#',name(*[2]),name(*[3]))" etc. The # characters prevent spurious matches.
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