Subject: RE: [xsl] Variable select="concat()" not loading variable. From: "Michael Kay" <mhk@xxxxxxxxx> Date: Thu, 24 Apr 2003 10:37:39 +0100 |
> > I am trying to concatinate a collection of text() strings > (see xsl below) however the variable (timestamps) is not > being filled with any data. Could someone tell me why? The > total number of timestamps to be concatinated is 10,000. You are trying to assign to a variable. Basic error - that's not how variables in XSLT work. It's not a procedural language like JavaScript. Read any number of posts about variable assignment, procedural vs declarative programming, etc, or any XSLT textbook. You want something like: <xsl:variable name="timespamps"> <xsl:for-each select="...."> <xsl:value-of select="."/> </xsl:for-each> </xsl:variable> Michael Kay Software AG home: Michael.H.Kay@xxxxxxxxxxxx work: Michael.Kay@xxxxxxxxxxxxxx > > Kind regards > > Simon > > > [code] > <!-- > <xsl:for-each select="ROW/TIMESTAMP"> > <xsl:if test="position() = 1"> > <xsl:element name="starttime"><xsl:value-of > select="." /></xsl:element> > </xsl:if> > <xsl:if test="position() = last()"> > <xsl:element name="endtime"><xsl:value-of select="." > /></xsl:element> > </xsl:if> > > <xsl:variable name="timestamps" > select="concat($timestamps, ./text())" /> > > <xsl:if test="position() != last()"> > <xsl:variable name="timestamps" > select="concat($timestamps, $delim)" /> > </xsl:if> > </xsl:for-each> > --> > > "Make it idiot proof, and someone > will make a better idiot" - Anon > > Institut fuer > Prozessdatenverarbeitung > und Elektronik, > Forschungszentrum Karlsruhe GmbH, > Postfach 3640, > D-76021 Karlsruhe, > Germany. > > Tel: (+49)/7247 82-4042 > E-mail : kelly@xxxxxxxxxx > > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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