[xsl] WITH-PARAM with node as argument?

[Andreas Schlegel <schlegelaw@xxxxxx>]

Hi,

I would like to write a with-param statement with a node as argument and 
handle this node in a template. But I don't know if it is possible or 
even what is the syntax. The following example is my current code which 
has to much arguments (IMHO). It would be great if I could reduce it to 
only 1 argument.

<xsl:call-template name="textfield">
  <xsl:with-param name="label" 
select="comp/attribute[@name='country']/@label"/>
  <xsl:with-param name="name" 
select="comp/attribute[@name='country']/@name"/>
  <xsl:with-param name="size" 
select="comp/attribute[@name='country']/@size"/>
  <xsl:with-param name="value" 
select="comp/attribute[@name='country']/@value"/>
</xsl:call-template>


<xsl:template name="textfield">
  <xsl:param name="label"/>
  <xsl:param name="name"/>
  <xsl:param name="size"/>
  <xsl:param name="value"/>
  <tr>
    <th align="left"><xsl:value-of select="$label"/></th>
    <td align="left" colspan="1">
      <xsl:element name="input">
        <xsl:attribute name="type">text</xsl:attribute>
        <xsl:attribute name="name"><xsl:value-of 
select="$name"/></xsl:attribute>
        <xsl:attribute name="size"><xsl:value-of 
select="$size"/></xsl:attribute>
        <xsl:attribute name="value"><xsl:value-of 
select="$value"/></xsl:attribute>
      </xsl:element>
    </td>
  </tr>	
</xsl:template>


Greetings,
Andreas



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