Subject: RE: [xsl] find previous node at the same level From: Sundar Shanmugasundaram <SSHANMUGASUNDARAM@xxxxxxxxxxxxx> Date: Wed, 30 Apr 2003 10:31:29 +0530 |
Use this template <?xml version="1.0"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output method="html" indent="yes" /> <xsl:template match="/o/home"> <xsl:apply-templates select="item"/> </xsl:template> <xsl:template match="item"> <xsl:if test="name((preceding-sibling::*)[last()])='group'">. blah blah </xsl:if> <xsl:if test="name((preceding-sibling::*)[last()])='item'">. blah blah </xsl:if> </xsl:template> </xsl:stylesheet> For the XML <?xml version="1.0"?> <o> <home> <group>group 1</group> <item>item one</item> <item>item two</item> <item>item three</item> <item>item four</item> <group>group 2</group> <item>item one</item> <item>item two</item> <item>item three</item> </home> </o> BFN, sundar -----Original Message----- From: Mark Ivs [mailto:markivs2003@xxxxxxxxx] Sent: Wednesday, April 30, 2003 5:30 AM To: XSL-List@xxxxxxxxxxxxxxxxxxxxxx Subject: [xsl] find previous node at the same level Hello, Here's how my xml looks. <home> <group>group 1</group> <item>item one</item> <item>item two</item> <item>item three</item> <item>item four</item> <group>group 2</group> <item>item one</item> <item>item two</item> <item>item three</item> </home> <xsl:apply-templates select="item"> if previous node is group... then do blah else if previous node is item.... then do blah </xsl:apply-templates> So when I am in item template how do I find what the previous node is ? (In my example it will be the item one nodes) Your help will be appreciated. Thanks. Mark __________________________________ Do you Yahoo!? The New Yahoo! Search - Faster. Easier. Bingo. http://search.yahoo.com XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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