Re: [xsl] finding the first element of a specific type

Subject: Re: [xsl] finding the first element of a specific type
From: Wendell Piez <wapiez@xxxxxxxxxxxxxxxx>
Date: Mon, 26 May 2003 15:54:51 -0400

The XPath "//register[@status ='direct' or @status='reserve'][1]" will return you all the register elements with status equal "direct" or "reserve" that are the first such child elements of their parents.

To get the first one in the document, use "(//register[@status ='direct' or @status='reserve'])[1]".

But I'd do it JP's way and use the preceding:: axis.


At 03:10 PM 5/26/2003, was written:
Here's my code:
<xsl:variable name="printable_register1" select="//register
                   [@status  ='direct' or @status='reserve'][1]"/>
<xsl:template match="register">
  <xsl:when test="generate-id(self::*)=generate-id($printable_register1)">
   ... do stuff
I want to find the first register that has either "direct" or "reserve"
status so that there will be no page break printed when that and only that
one is output.  But it ain't working.  Can anyone help me.

I'd try the preceding axis: <xsl:template match="register"> <xsl:choose> <xsl:when test="not(preceding::register[@status ='direct' or @status='reserve'])"> ...

BTW without testing it specifically I'd say your approach
should work too, although it's a bit...unconventional
(for example, most people tend to use . instead of self::*).

___&&__&_&___&_&__&&&__&_&__&__&&____&&_&___&__&_&&_____&__&__&&_____&_&&_ "Thus I make my own use of the telegraph, without consulting the directors, like the sparrows, which I perceive use it extensively for a perch." -- Thoreau

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