RE: [xsl] Grouping the same set by multiple criteria

[Erika Marlow <EMarlow@xxxxxxxxxxxxxx>]

<Ken said>
At 2003-05-28 09:49 -0500, Erika Marlow wrote:
>I have used the Muenchian
>technique to find the unique groups, but I am stuck on how to get the
counts
>for the different groupings.

Go back to the key table and count the number of members of the table for 
which the Muenchian method was used to collect common values.

For example, if you used

   //transaction[ generate-id(.)=
                  generate-id(key('bydates',original_request/inquiry/@date))
]

then you can get the count of those by that date using:

   count( key( 'bydates', original_request/inquiry/@date ) )

I hope this helps.

............... Ken
</Ken said>

I don't think I quite understand.  The first line produces the set of
transaction nodes that have unique dates; for the example data provided
previously: <transaction> - 20030128 and <transaction> - 20030528.  The
second line then gives a result of 2, the number of nodes in the key set not
the number of transaction nodes that match 20030128 and the number of nodes
that match 20030528 and so on.

Maybe a different way to phrase my question is, how do I count the number of
transactions that match the criteria date==20030128, site==0000 and
payer==00003?

I am able to find the unique dates, sites and payers to sort by, but I am
unable to count each set.

Thanks,
Erika

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