Subject: RE: [xsl] invalid xpath expression From: "Lars Huttar" <lars_huttar@xxxxxxx> Date: Wed, 28 May 2003 13:23:33 -0500 |
> my xsl file is: > > <xsl:choose> > <xsl:when test=".=list"> > <xsl:variable name="n" select="12"/> > </xsl:when> > <xsl:otherwise> > <xsl:variable name="n" select="2"/> > </xsl:otherwise> > </xsl:choose> > ------------------- > <xsl:variable name="m" select="$n"/> > > i receive the error :invalid xpath expression! > so what the problem in <xsl:variable name="m" select="$n"/>? A variable is only in scope in the element in which it is declared. So the first n is only in scope within the first <when>. The second n is only in scope within the <otherwise>. No n is in scope for your select="$n". To fix the problem, put the <choose> inside the <variable name="n">: <xsl:variable name="n"> <xsl:choose> <xsl:when test=".=list">12</xsl:when> etc. </xsl:variable> <xsl:variable name="m" select="$n" /> This is a kind of thing that is usually taught in introductory textbooks for XSLT, such as Jeni Tennison's. Lars XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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