Subject: RE: [xsl] Access all values From: David Carlisle <davidc@xxxxxxxxx> Date: Wed, 28 May 2003 20:56:38 +0100 |
Hello, I show you the example, <xsl:variable name="langs" select="terms/lang"/> langs will access all the childs of the select. How can I get all of them in just one varible, like if it was an array? I need this because I have it a form and I have to submit an array of langs. Thanks, Ricardo Saraiva. Sorry but that isn't an example of anything, you'd need to show a sample input and a required output. I'm not sure what you mean by "childs of the select", the expression would select all lang children of terms children of the current node. They are all in "one variable", accessed by $langs. I can only assume by "all" you mean all of the lang nodes in the document rather than just grandchildren of the current node, that would be <xsl:variable name="langs" select="//lang"/> But it's not clear that you need a variable at all, usually when beginners expect to use a variable in XSLT then it turns out that no variable is needed. David XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
Current Thread |
---|
|
<- Previous | Index | Next -> |
---|---|---|
Thread | [xsl] Re: Flat -> Hierarchy --- Con, Lars Huttar | |
Date | [xsl] Re: Flat -> Hierarchy --- Con, Lars Huttar | |
Month |