RE: [xsl] Extracting link information from xml document and displaying it in browser as hyperlink

Subject: RE: [xsl] Extracting link information from xml document and displaying it in browser as hyperlink
From: bmcleere@xxxxxxxxxx
Date: Tue, 10 Jun 2003 14:19:01 +0100
Jim,
- thanks very much for that. The following line of code works perfectly.
<a href="{.}"><xsl:value-of select="."/></a>

Very much appreciated:-) 
Kindest regards,

Brenda


xsl-list@xxxxxxxxxxxxxxxxxxxxxx wrote:

<  
<  
<  
<  > -----Original Message-----
<  > From: bmcleere@xxxxxxxxxx [mailto:bmcleere@xxxxxxxxxx]
<  > Hi,
<  > 
<  > I have an xml document with a <location> tag amongst others e.g.
<  > 
<  >  <location> http://someserver.ie</location>. 
<  >  
<  >  I want to retrieve the URL information and display it as a 
<  >  hyperlink in the browser.
<  >  
<  >  Currently, I can view the URL information but it is not a hyperlink. 
<  >  
<  >  I thought of using the following:-
<  >  <xsl:template match="technical/location">
<  >  <a href="http://{@link}";><xsl:value-of select="."/></a>
<  >  </xsl:template>
<  
<  a few things,
<  
<  - where is your @link attribute ? I only see a location element, also u have location already matched e.g. should work;
<   
<  <a href="{.}"><xsl:value-of select="."/></a>
<  
<  i have written it again, xplicitly calling the location element
<  
<  <a href="{location}"><xsl:value-of select="location"/></a>
<  
<  
<  - btw prefixing an http:// to your location would result in http://http://someserver.ie , so unless thats a typo that would cause your problem with the double http prefix
<  
<  gl, jim fuller
<  
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