Subject: Re: [xsl] xhtml and different namespace From: "Joe Fawcett" <joefawcett@xxxxxxxxxxx> Date: Wed, 11 Jun 2003 09:47:20 +0100 |
From: Björn Boxstart <Boxstart@xxxxxxxx> Reply-To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx> Subject: [xsl] xhtml and different namespace Date: Wed, 11 Jun 2003 09:37:29 +0200
Hello,
Ik have a strange problem with a document that I want to process. The document conforms to the XHTML dtd. The only thing I want to do is remove the DTD declaration and add a new top element. Although I set the output method to be xml, the document always is being returned as xhtml with the xhtml namespace.
I want to transform this resulting document (see below) with another xsl-t stylesheet.
<?xml version="1.0" encoding="UTF-8"?>
<Iisg source="biografie"><biography>
<xhead>
<meta xmlns="http://www.w3.org/1999/xhtml" name="generator" content="HTML Tidy for Windows (vers 1st August 2002), see www.w3.org"/>
<meta xmlns="http://www.w3.org/1999/xhtml" http-equiv="content-type" content="text/html; charset=iso-8859-1"/>
<link href="styles/bwsa.css" type="text/css" rel="stylesheet"/>
<title xmlns="http://www.w3.org/1999/xhtml">Piet Aalberse</title> </xhead>
<body xmlns="http://www.w3.org/1999/xhtml" bgcolor="#ffffff"> <table> ... more data to go here ... </table> </body> </Iisg>
My problem is that the elements that have the namespace declaration as an attribute seem to have a prefix and therefore are not processed by my templates.
Something like match='title' doesn't work on a template while match="*[local-name() = 'title']" does. When I want to display the prefix (e.g. by <xsl:value-of select="substring-before(name(),':')" this doesn't return anything at all.
It looks like when I make a template for the body element like:
<xsl:template match="*[local-name() = 'body']"> <xsl:apply-templates select="table" /> </xsl:template>
This doesn't seem to work because it looks like the table is part of another namespace as the body element. Does anybody know what I'm doing wrong? I tried several processors and they all have sort of the same result, so I think that I'm the problem and not the processor ;-(
Thanks in advance!
Best regards,
bjorn
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