Subject: Re: [xsl] How to find all parents having the same child? From: David Carlisle <davidc@xxxxxxxxx> Date: Wed, 18 Jun 2003 10:12:03 +0100 |
> Given that, I would like to extract all parents for > eac Given that your original question didn't even mention that you wanted to compare the values of name attributes of elements or that your elements even any attributes at all, how did you think that anyone had a hope of guessing that this is what you wanted? something like this <xsl:stylesheet .... <xsl:key name="p" match="*" use="@name"/> <xsl:template match="/"> <xsl:for-each select="//*[generate-id()=generate-id(key('p',@name))] <xsl:value-of select="@name"/> <xsl:text>: </xsl:text> <xsl:for-each select="key('p',@name)"> <xsl:valuue-of select="../@name"/> <xsl:if test="position()<last()">, </xsl:if> </xsl:for-each> </xsl:for-each> </xsl:template> ... David ________________________________________________________________________ This e-mail has been scanned for all viruses by Star Internet. The service is powered by MessageLabs. For more information on a proactive anti-virus service working around the clock, around the globe, visit: http://www.star.net.uk ________________________________________________________________________ XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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