Subject: [xsl] grouping children of same name parents under one common tag From: abickford@xxxxxxxxxx Date: Thu, 19 Jun 2003 15:13:25 -0400 (EDT) |
Good afternoon. I'm new to xsl, and need some advice on how to format a document. I'm looking to find all the tags with the same name, collect their children and put them all under one common tag. Part of the problem is, I have no idea what the tag names will be. Let's say the xml I want to transform looks like this: <root> <bob> <someTag>content1</someTag> </bob> <bob> <someTag>content2</someTag> </bob> <sue> <someTag>content3</someTag> </sue> <warren> <someTag>content4</someTag> </warren> <warren> <someTag>content5</someTag> </warren> </root> I would like the output to be: <root> <bob> <someTag>content1</someTag> <someTag>content2</someTag> </bob> <sue> <someTag>content3</someTag> </sue> <warren> <someTag>content4</someTag> <someTag>content5</someTag> </warren> </root> Again, I don't know the tag names ahead of time(Bob, Sue, and Warren are just examples). I'm not sure how to tell xsl that I want to: 1) compare the current node's name with its siblings' names. 2) if a name match is found, adopt the matched sibling's children. (matched sibling can die now, how nice of me ;) 3) keep looking for more siblings with matching names, adopting their children if more matches are found. 4) don't repeat steps 1-3 for matched siblings (not an issue if they were killed in step 2 when their children were taken away). Thanks for any help. I'm having trouble accomplishing this, even tho I know exactly what I want. XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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