Re: [xsl] xpath question

[florian <csshsh@xxxxxxxxxxxxxxx>]

On Sonntag, Juni 22, 2003, at 10:37  Uhr, Mike Brown wrote:

> florian wrote:
> > hi!
> >
> > i unfortunately cant think of a xpath statement for this:
> >
> >
> > i want to get all the child nodes of my current node, which
> > have an node with the name 'bar' and where the content
> > of the node is 'apples'..
> >
> > the tricky part now is that the name 'bar' and 'apples' is defined
> > in another node somewhere in the document.
> >
> > *[*[local-name() = /someNode/@theAttributeWithTheValueBar] =
> > /fruits/roundOnes[1]]
> >
> > doesnt really seem to work..
>
> <xsl:variable name="barname" 
> select="string(/someNode/@theAttributeWithTheValueBar)"/>
> <xsl:variable name="fruitname" select="string(/fruits/roundOnes[1])"/>
>
> then
>
> *[local-name() = $barname and . = $fruitname]
>
> You can do it without variables but this way it gives the processor
> an opportunity to
>  optimize.

thanks alot, mike!

im suing that statement in an for-each element.. so im wondering if 
there is
anyway to return the parent of the bar node and not the bar note 
itself..


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