RE: [xsl] Looping in XSLT(old question, but maybe new problem)

["Liu Shuai" <shuai@xxxxxxxxxxxxxxxxx>]

Mike,

Thank you for your response. I got another issue.

I have the template like this:
<xsl:template match="foo">
	<table>
      	<xsl:for-each select="bar">
		<xsl:sort select="@id" data-type="number"/>
            <xsl:if test="(number(position()) mod 3) = 1">
			<tr>
                  	<td>
                        	<xsl:value-of disable-output-escaping="yes"
select="someElement"/>
	                  </td>
				<td>
					<xsl:for-each select="following-sibling::bar[position()=1]">
						<xsl:value-of disable-output-escaping="yes" select="someElement"/>
					</xsl:for-each>
				</td>
				<td>
					<xsl:for-each select="following-sibling::bar[position()=2]">
						<xsl:value-of disable-output-escaping="yes" select="someElement"/>
					</xsl:for-each>
				</td>
			</tr>
		</xsl:if>
		</xsl:for-each>
	</table>
</xsl:template>

As you see, I sort bar based on some rule, but when I get the next two
element, how can I keep
the order? Looks to me following-sibling fetch element based on the orginal
order in the source
file.

Thank you.
LS

-----Original Message-----
From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx
[mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx]On Behalf Of Mike Brown
Sent: Monday, June 23, 2003 10:04 PM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: Re: [xsl] Looping in XSLT(old question, but maybe new problem)


Liu Shuai wrote:
> Hi, all
>
> I am trying to write a template that will generate a table based on a xml
> file and right now I don't have any
> clue how to do it.
>
> If I have a source file looks like this
>
> <foo>
> 	<bar id='1'>
> 		<someElement>a</someElement>
> 	</bar>
> 	<bar id='2'>
> 		<someElement>b</someElement>
> 	</bar>
> 	<bar id='3'>
> 		<someElement>c</someElement>
> 	</bar>
> 	<bar id='4'>
> 		<someElement>d</someElement>
> 	</bar>
> 	<bar id='5'>
> 		<someElement>e</someElement>
> 	</bar>
> 	...
> </foo>
>
> Can I write a style sheet that will transform the source file above to a
> html table like this?
>
> <table>
> 	<tr>
> 		<td>a</td>
> 		<td>b</td>
> 		<td>c</td>
> 	</tr>
> 	<tr>
> 		<td>d</td>
> 		<td>e</td>
> 		<td>&nbsp;</td>
> 	</tr>
> 	...
> </table>
>
> Basicly, I want to generate N columns per row but I don't know how many
> "bar"s I have in the source file.

Select all bar elements for processing.
In the template that matches a bar element, if position() returns
a value that when divided by 3 has a remainder of 1, generate a table row
element. Inside that element, create cells for the current node and its
first two following siblings.


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