Re: [xsl] number continuation problem

[Jeni Tennison <jeni@xxxxxxxxxxxxxxxx>]

Hi Andrew,

> A new twist is that there can be many <elseif>'s to an <if>
> (naturally enough), so the data can take the form:
>
> <if/>
> <elseif/>
> <elseif/>
> <elseif/>
> <if/>
> <elseif/>
>
> Is there a neat trick of getting all following-siblings while they
> are of a certain name (as if they are processed linearly).

In XSLT 1.0, use a key: index all the <elseif> elements by their
immediately preceding <if> element:

<xsl:key name="elseifs" match="elseif"
         use="generate-id(preceding-sibling::if[1])" />

Then, when on an <if> element, you can get all the related <elseif>
elements with:

  key('elseifs', generate-id(.))

Or you can just do it with:

  following-sibling::elseif[generate-id(preceding-sibling::if[1]) =
                            generate-id(current())]

Or you can step through them one-by-one recursively.
                            
Note that your solution:

  following-sibling::elseif[not(preceding-sibling::if[2])]

collects together all the <elseif> elements that have 0 or 1 preceding
sibling <if> elements. So, for example, if you're on the second <if>
of the example above, it won't select the following <elseif> because
it does have a second preceding sibling <if> element.

Cheers,

Jeni

---
Jeni Tennison
http://www.jenitennison.com/


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