RE: [xsl] how to test for the element type of the current node

["Michael Kay" <mhk@xxxxxxxxx>]

The logic

<for-each select="X">
  <choose>
     <when name="A">
     <when name="B">

is needed so often that XSLT provides a special construct for it: it's
called xsl:apply-templates. Use it!

Michael Kay


> -----Original Message-----
> From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx 
> [mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx] On Behalf Of 
> Godmar Back
> Sent: 02 July 2003 08:51
> To: XSL-List@xxxxxxxxxxxxxxxxxxxxxx
> Subject: [xsl] how to test for the element type of the current node
> 
> 
> 
> Hi,
> 
> what expression do I use if I need to test the type of the 
> current node in a for-each loop?
> 
> Say I have a DTD that has	
> 
> 	<!ELEMENT A (B|C)*>
> 
> and I want to write
> 
> <xsl:template match="A">
>     <xsl:for-each select="*">
> 	<xsl:choose>
> 	    <xsl:when test="if this node is a B"> <--- this is 
> what I can't figure out
> 		apply-templates for B
> 
> 		...
> 	    <xsl:otherwise>
> 		do something else for C
>     ...
> 
> 
> I tried ".=B" inside the test, which doesn't work, I tried just "B", 
> I tried "boolean(B)", nothing works.
> 
> Note that I believe that using <xsl:template match="B"> won't 
> solve my problem because I need to do something specific that 
> I only need to if the 
> B element is nested inside  the A element.
> 
> This seems such an elementary thing to do (!?), but maybe I 
> still don't understand XSL well enough to see an alternative.
> 
> Thanks!
> 
> 	- Godmar
> 
> 
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