Re: [xsl] XSL/XPath Dynamic sort key

[David Carlisle <davidc@xxxxxxxxx>]

} <xsl:sort
}    select="*[name()=$sort_select_lvl_1]\*[name()=$sort_select_lvl_2]" 


\ isn't Xpath: you want /
As it is you should get a syntax error.

>  If I remove the "\" i get a number expected error
yes because * is multiplication.

> xsl:sort select="concat('author','/','last_name')" />
> is not the same as
> <xsl:sort select="author/last_name" />

No, concat produces a string, so it's the same as
<xsl:sort select="'author/last_name'" />
which is a legal expression, but not what you want.

<xsl:sort select="*[name()=$sort_select]|author/*[name()=$sort_select]" 
data-type="{$sort_data_type}" order="{$sort_order}" />

and just set the sort_select param to be 'uid' or 'last_name' or whatever
you want. In each case one branch of the | will return nothing, but
that's OK.

David

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