Subject: RE: [xsl] Using not(...a nd ... ) to select nodes From: "Lars Huttar" <lars_huttar@xxxxxxx> Date: Fri, 11 Jul 2003 15:37:49 -0500 |
Michael Kay wrote: > current() always refers to the node that "." would refer to if you > replaced the whole XPath expression containing the call on current() > with ".". I already said this was helpful, but let me just emphasize that this statement would be a useful addition to the current() function page (463) in the XSLT Programmer's Reference! I'd been studying that page, but until you said the above, I still wasn't sure of the answer to my question. The bullet about <xsl:for-each> says that "each selected node in turn becomes the current node." That sounds like it means only nodes that actually pass the select="" test [each *selected* node] become the current node. But I wasn't 100% sure until the above made it more explicit. Regards, Lars XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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