Subject: Re: [xsl] how to set the bgcolor of a table cell to the value of an XML attribute From: David Totten <xsl@xxxxxxxxxxxxxx> Date: Fri, 18 Jul 2003 07:54:29 -0400 |
Hi everyone,
each stock has it's own row and each cell represents a trading day. i'm trying to set the bgcolor of each cell to the color(in hex) for that particular node. my knowledge of XSLT is quite limited and i have no idea how to do this. i've attached both the xslt file and a snippet of the xslt file. i'm using Xalan and Xerces thru JAXP. pls help!
thanks....Zain
here is a sample of my XML file....
<Equities-List>
<Equity name="CP">
<EquityNode date="2000-01-03" close="9.6">
<Color hex="246f15">
</EquityNode> <EquityNode date="2000-01-04" close="9.7">
<Color hex="227017">
</EquityNode> <EquityNode date="2000-01-05" close="9.9">
<Color hex="1f731a">
</EquityNode> </Equity>
</Equities-List>
and here's my XSLT file....
<xsl:template match="/">
<html>
<body>
<table>
<xsl:for-each select="//Equity">
<tr>
<td> <xsl:value-of select="@name"> </td>
<td> <xsl:apply-templates select="EquityNode"/>
</td> </xsl:for-each>
</table>
</body>
</html>
</xsl:template>
<xsl:template match=EquityNode"> <td bgcolor="<!-- SET COLOR TO @HEX IN COLOR NODE -->"> <xsl:value-of select="@date"/> <xsl:text> close= </xsl:text> <xsl:value-of select="@close"/> <br/><br/> <xsl:apply-templates select="Color"/> </td> </xsl:template>
<xsl:template match=Color"> <xsl:text> Hex= </xsl:text> <xsl:value-of select="@hex"/> </xsl:template>
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