Subject: RE: [xsl] String literal error From: Américo Albuquerque <melinor@xxxxxxx> Date: Tue, 29 Jul 2003 17:03:28 +0100 |
Hi. > -----Original Message----- > From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx > [mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx] On Behalf Of > Arthur Maloney > Sent: Tuesday, July 29, 2003 10:00 AM > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > Subject: [xsl] String literal error > > > Hello xsl-list, > > <xsl:param name="delimiter" select=" ',' "/> > <xsl:param name="quote-mark" select=" ' "/> > > I am using above to produce SQL csv text file > Top one works fine > > The 2nd gives error "a string literal was not enclosed" > Dear xsl-ers , > > <xsl:param name="delimiter" select=" ',' "/> > <xsl:param name="quote-mark" select=" ' "/> > > I'm using the above to produce SQL csv text file. > > 1st works fine > 2nd gives error "a string literal was not enclosed" Use <xsl:param name="quote-mark" select=" '&_quot;' "/> without the '_' > > I'm using <xsl:text>'</xsl:text> as a work around. > > > How do you put ' or " into a parameter ? > > > -- > Best regards, > Arthur mailto:ArthurMaloney@xxxxxxxxxx > > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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