Subject: RE: [xsl] Incrementing number in a for loop ?? From: "G. Ken Holman" <gkholman@xxxxxxxxxxxxxxxxxxxx> Date: Thu, 31 Jul 2003 10:41:43 -0400 |
When i m parsing my xsl file i m creating quotes like this and it is HARDCODED
and this I counted and put into my xsl file as show below where at someplace i
need like this.
<xsl:text> ``````````````````````````````</xsl:text> And at other place i need something like this. <xsl:text> ``````</xsl:text> ... int quoteCount = 30; // for example this many quotes i need for(int i = 0; i < quoteCount ; i++) printf("`");
T:\ftemp>type dipesh.xsl <?xml version="1.0" encoding="iso-8859-1"?> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:template match="/"> <xsl:text>First is 30: </xsl:text> <xsl:call-template name="do-quotes"> <xsl:with-param name="count" select="30"/> </xsl:call-template> <xsl:text>
Second is only 20: </xsl:text> <xsl:call-template name="do-quotes"> <xsl:with-param name="count" select="20"/> </xsl:call-template> </xsl:template>
<xsl:template name="do-quotes"> <xsl:param name="count" select="0"/> <xsl:if test="$count"> <xsl:text>'</xsl:text> <xsl:call-template name="do-quotes"> <xsl:with-param name="count" select="$count - 1"/> </xsl:call-template> </xsl:if> </xsl:template>
</xsl:stylesheet> T:\ftemp>saxon dipesh.xsl dipesh.xsl First is 30: '''''''''''''''''''''''''''''' Second is only 20: '''''''''''''''''''' T:\ftemp>
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G. Ken Holman mailto:gkholman@xxxxxxxxxxxxxxxxxxxx Crane Softwrights Ltd. http://www.CraneSoftwrights.com/s/ Box 266, Kars, Ontario CANADA K0A-2E0 +1(613)489-0999 (F:-0995) ISBN 0-13-065196-6 Definitive XSLT and XPath ISBN 0-13-140374-5 Definitive XSL-FO ISBN 1-894049-08-X Practical Transformation Using XSLT and XPath ISBN 1-894049-11-X Practical Formatting Using XSL-FO Member of the XML Guild of Practitioners: http://XMLGuild.info Male Breast Cancer Awareness http://www.CraneSoftwrights.com/s/bc
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