[xsl] Assigning unique id to new node using generate-id()

[<kyle.himmerick@xxxxxxxxxxxxxx>]

I'm having unexpected results with the generate-id() function.

I am attempting to add a new node to an existing document and assigning a new and
*unique* id attribute to the new node.

Sample XML:
<profile>
<credential id="N400012">
		<username><![CDATA[user1]]></username>
		<password><![CDATA[pass1]]></password>
		<description><![CDATA[my description]]></description>
		<lastModified>2003-08-07 14:19:13</lastModified>
	</credential>
	<credential id="N40002B">
		<username><![CDATA[user2]]></username>
		<password><![CDATA[pass2]]></password>
		<description><![CDATA[another id]]></description>
		<lastModified>2003-08-06 16:03:52</lastModified>
	</credential>
</profile>

I'd like this stylesheet to copy all existing credential nodes and create a new
node assigning a unique id with generate-id().  It appears as if the generate-id
call doesn't observe existing id's in the current/copied credential nodes.  So I
end up with duplicate (illegal) id's.  I've tried passing several context nodes
to the generate-id() function, but with no luck.

Sample XSL:
	<xsl:template match="/profile">
		<profile>
			<xsl:for-each select="credential">
				<xsl:copy-of select="."/>
			</xsl:for-each>
			<credential>
				<xsl:attribute name="id">
					<xsl:value-of select="generate-id()"/>
				</xsl:attribute>
				<username><xsl:value-of select="$username"/></username>
				<password><xsl:value-of select="$password"/></password>
				<description><xsl:value-of select="$description"/></description>
				<lastModified><xsl:value-of
select="java:getCurrentDateTimeGMT($dateHelper)"/></lastModified>
			</credential>
		</profile>
	</xsl:template>

My current workaround is to transform twice.  The first transformation appends
the new credential node.  The second transformation assigns an id (using
generate-id()) to any credential nodes without an id (probably only newly
created).  Seems like I should be able to do it all in one transform.

Thanks for your help.



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