AW: [xsl] limit count() to nodes with a position() < the posti on of the current node

["Zink, Juergen" <Juergen.Zink@xxxxxxxxxxxxxxxxxxxx>]

Hi,

the it is a grouping problem. Have a look at www.jenitennison.com
Define a key with 

<xsl:key name="linkCount" match="visit" use="lid"/>

>History >> Home(2) :: Section 2

All Home are now grouped.
Iterate above all the nodes foreach and check if 
it is the first element in a group. Then you can 
print (output) the element.

<xsl:for-each select="//visit">

<xsl:if test="generate_id(key('linkCount',lid))=generate-id(.)">

Or you can count the number of items in the group.
with count(key('linkCount', lid)) to get the (2) after Home

>History >> Home(2) :: Section 2

The code is not tested. Hope it works.

Kind regards,

Juergen

-----Ursprüngliche Nachricht-----
Von: M. David Peterson [mailto:conners_dad@xxxxxxx]
Gesendet am: Dienstag, 9. September 2003 08:44
An: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Betreff: Re: [xsl] limit count() to nodes with a position() &lt; the
postion of the current node

Ah, yes, I see the mistake regarding the position() of the 'lid' node.

What I am trying to do is this...  I have a history file that allows the 
user to view the last 5, 10, or 25 links they have visited on the site.  The

count simply tells the user how many times they have visited that link.  To clean things up for them I want to check during each pass through the 
for-each loop if the link in there history file has already been rendered to

the output.  If it has then I want it to skip over that entry and move on to

the next.  So, for example, if the history file looked like this...

<history>
    <visit>
        <loc>foo</loc>
        <subloc>bar</subloc>
        <lid>AAA001</lid>
    </visit>
    <visit>
        <loc>foofoo</loc>
        <subloc>barbar</subloc>
        <lid>AAA002</lid>
    </visit>
    <visit>
        <loc>foo</loc>
        <subloc>bar</subloc>
        <lid>AAA001</lid>
    </visit>
</history>

Instead of the history output listing all the entries like this (I 
previously match the 'lid' to a master file to get the common name for the link and then display the common name. e.g AAA001 = Home and AAA002 = Section 2)...

History >> Home :: Section 2 :: Home

It would list it like this...

History >> Home(2) :: Section 2

Any ideas?

Best regards,

M.




----- Original Message ----- 
From: "Zink, Juergen" <Juergen.Zink@xxxxxxxxxxxxxxxxxxxx>
To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx>
Sent: Tuesday, September 09, 2003 12:07 AM
Subject: AW: [xsl] limit count() to nodes with a position() &lt; the postion

of the current node


> Hi,
>
> the position of <lid> is the number of preceding siblings.
> In your example should be 4, <loc>, <sub>, <date> sibling before.
>
> Maybe you can use a foreach with select="//lid".
> All the lid elements in a node set in document order.
> Then you can use position() within the loop.
>
> But I don't understand your questions fully.
> What do you want to achieve?
>
> Kind regards,
>
> Juergen
>
> -----Ursprüngliche Nachricht-----
> Von: M. David Peterson [mailto:conners_dad@xxxxxxx]
> Gesendet am: Dienstag, 9. September 2003 07:23
> An: xsl-list
> Betreff: [xsl] limit count() to nodes with a position() &lt; the postion
> of the current node
>
> Hi all,
>
> Ive got an interesting one for you...
>
> Ive got the following key...
>
> <xsl:key name="linkCount" match="lid" use="."/>
>
> that uses the following xml...
>
> <history>
>     <visit>
>       <loc>life</loc>
>       <subloc>main</subloc>
>       <date>9/8/2003 10:49:58 PM</date>
>       <lid>AAD001</lid>
>     </visit>
> </history>
>
> to give me the total count of all nodes that have the value of the current

> context...
>
> <xsl:value-of select="count(key('linkCount', lid))"/>
>
> This works perfectly as it returns the total count of all nodes that have > the same value as the current context node...
>
> But I want to take this one step further and return the count of all nodes

> that have a position() that is less than the position of the current node.

> Taking the position() of the context node out of the equation I thought it

> would as simple as this (I used 5 as a test parameter)...
>
> <xsl:key name="linkCount" match="lid[position() &lt; 5]" use="."/>
>
> I expected it to return the count of the nodes that matched the current
> context node as long as there postion was less than 5.  But it didn't.  It

> returned the total count for the entire xml tree.
>
> So, my questions are...  1)What do I need to change to get the above 
> example
>
> to work and 2)How could I then take it one step further and use the
> position() of the current context node as the parameter to test against > the position() of the test nodes?
>
> Your help is much appreciated!
>
> Best Regards,
>
> M.David
>
>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
>
>
>
****************************************************************************
*
> Diese E-Mail enthaelt vertrauliche und/oder rechtlich geschuetzte
> Informationen. Wenn Sie nicht der richtige Adressat sind oder diese
> eMail irrtuemlich erhalten haben, informieren Sie bitte sofort den
> Absender und vernichten Sie diese Mail. Das unerlaubte Kopieren
> sowie die unbefugte Weitergabe dieser Mail ist nicht gestattet.
>
> This e-mail may contain confidential and/or privileged information.
> If you are not the intended recipient (or have received this e-mail
> in error) please notify the sender immediately and destroy this e-mail.
> Any unauthorized copying, disclosure or distribution of the material
> in this e-mail is strictly forbidden.
>
****************************************************************************
*
>
>
>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
>
> 

 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list


*****************************************************************************
Diese E-Mail enthaelt vertrauliche und/oder rechtlich geschuetzte 
Informationen. Wenn Sie nicht der richtige Adressat sind oder diese 
eMail irrtuemlich erhalten haben, informieren Sie bitte sofort den 
Absender und vernichten Sie diese Mail. Das unerlaubte Kopieren 
sowie die unbefugte Weitergabe dieser Mail ist nicht gestattet.

This e-mail may contain confidential and/or privileged information. 
If you are not the intended recipient (or have received this e-mail 
in error) please notify the sender immediately and destroy this e-mail. 
Any unauthorized copying, disclosure or distribution of the material 
in this e-mail is strictly forbidden.
*****************************************************************************


 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list