Subject: Re: [xsl] Random number From: Dimitre Novatchev <dnovatchev@xxxxxxxxx> Date: Wed, 24 Sep 2003 06:39:50 -0700 (PDT) |
> I need generate a random number and concatenate with > "x" to put like a > ID in a node. These numbers have to be always > different. > > <node id="x121334"> > </node> > <node id="x133543"> > </node> > > Can somebody help me? First of all, please note thatthere isn't anything like "a single random number" Randomness by definition is aproperty of all numbers in a (potentially infinite) sequence of numbers. Therefore, you have to access aservice, which gives you a sequence of random numbers with the length you desire. This is provided in XSLT by the FXSL library. See: "Casting the Dice with FXSL: Random Number Generation Functions in XSLT" at: http://fxsl.sourceforge.net/articles/Random/Casting%20the%20Dice%20with%20FXSL-htm.htm But you also need them all to be different (unique). How to do this has been demonstrated a year ago in this list on the topic of "Randomizing a node-set" -- see e.g. http://sources.redhat.com/ml/xsl-list/2002-05/msg00182.html or http://www.topxml.com/code/default.asp?p=3&id=v20020504013704 The idea is that if a sequence of N unique random numbers is wanted, then we produce a sequence of N random numbers in the range (0, 1] and scale all of them so that the kth number is scaled in the interval (0, k]. So what you need is produced by the template named "_randomRecursiveIndex". And this is part of the file randomList.xsl, contained in FXSL. ===== Cheers, Dimitre Novatchev. http://fxsl.sourceforge.net/ -- the home of FXSL P.S. Chances are that what you really need is not random numbers at all -- then just use the generate-id() function/ __________________________________ Do you Yahoo!? Yahoo! SiteBuilder - Free, easy-to-use web site design software http://sitebuilder.yahoo.com XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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