[xsl] Putting characters in an element

[Harm Kok <h.kok@xxxxxxxxxxxxxxx>]

Hi,

I am having the following problem. I would like to put a list number in 
a seperate element and preserve the other in-line elements.

input:
<?xml version="1.0"?>
<root>
<al>1. This is some very <emphasis>important</emphasis> tekst.</al>
<al>2. And a second line</al>
<al>And a last line</al>
</root>

desired output:
<li><li.nr>1.</li.nr><al>This is some very 
<emphasis>important</emphasis> tekst.</al></li>
<li><li.nr>2.</li.nr><al>And a second line</al></li>
<al>And a last line</al>

I can use XSLT 2 for the solution, but even with this I have not been 
able to solve the problem.
I have tried the following solution. It works perfectly with strings, 
but the inline element <emphasis> is not copied to the output.

Stylesheet:
<xsl:template match="al">
   <xsl:param name="first-string">
       <xsl:value-of select="substring-before(., ' ')"/>
   </xsl:param>

   <xsl:choose>
   <xsl:when test="matches($first-string,'\d')">
       <li>
           <xsl:analyze-string select="." regex="^\d\. ">
             <xsl:matching-substring>
               <nr><xsl:value-of select="."/></nr>
             </xsl:matching-substring>
             <xsl:non-matching-substring>
               <al><xsl:copy-of select="."/>
               </al>
             </xsl:non-matching-substring>
           </xsl:analyze-string>
       </li>
   </xsl:when>
   <xsl:otherwise>
       <al><xsl:copy-of select="descendant::node()"/></al>
   </xsl:otherwise>
   </xsl:choose>
</xsl:template>

How can I achieve this without nodes in stead of strings (in XSLT1.0 or 
XSLT2.0)?

Regards,

Harm




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