Re: [xsl] problem - generating XML schema via XSLT

[Christian Sell <christian.sell@xxxxxxxxxxxxx>]

Michael Kay wrote:
> Namespace declarations in the source document are translated by the XML
> parser into namespace nodes, they are not treated by XSLT as attribute
> nodes. Therefore, a namespace declaration can never contain an attribute
> value template (because it isn't an attribute).
>
> You need to produce in the result tree a namespace node whose name
> (=prefix) is "" and whose string value (=namespace URI) is "test". (It's
> very confusing that you chose to use the name "prefix" to refer to the
> namespace URI!

yes. In my case, they happen to be equivalent - but the wording was wrong.

> In XSLT 2.0 you can do this with
>
> <xsl:namespace name=""><xsl:value-of select="@prefix"/></xsl:namespace>
>
> In 1.0 there is no direct way of doing this. The nearest equivalent is:
>
> <xsl:variable name="dummy">
>   <xsl:element name="e" namespace="{@prefix}"/>
> </xsl:variable>
>
> <xsl:copy select="xx:node-set($dummy)/*/namespace::*[.=@prefix]"/>
>
> This creates a dummy element in the required namespace, and then copies
> the required namespace node to the result tree.

amazingly, this does not yield any change in the output document. I am 
using Xalan (where the function is named nodeset as opposed to 
node-set). The new namespace decl does not appear.

thanks,
christian


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