Subject: [xsl] Muenchian grouping help - removing 'duplicates' from a nodeset From: <Laura@xxxxxxx> Date: Thu, 9 Oct 2003 14:32:12 +0100 |
Hi all, This is probably quite a basic question, but I've been scratching my head over it all day and I could use some guidance. I have an XML file which is going to be used as a "dictionary" for an internationalised web application. The structure of he file is like so: <dictionary> <text>foo</text> <text>bar</text> <text>foo</text> <text>baz</text> <text>foobar</text> (etc...) </dictionary> The file contains quite a few "duplicates" (in terms of the text() content of the node), and I've been trying to figure out a way to strip out all the dupicates, leaving me with an XML file with only unique <text> elements. I wrote an XSL to identify all the duplicates, and print them out [basically using: test="current() = following-sibling::text or current() = preceding-sibling::text"] But now I want to actually remove the duplicates and create a new XML file in the output tree. I think they way to do this is via Muenchian grouping. I know what I need to do: group all the <text> elements by their text() content; and select only the first one in each group. But I've followed the guidelines on Jeni Tennison's XSLT pages and I can't seem to get my head around how keys actually work. So far I have tried (these are obviously just sample lines from my XSL): <xsl:key name="text-by-content" match="text" use="normalize-space(text())" /> And then: <xsl:apply-templates select="text[generate-id(.) = generate-id(key('text-by-content', text())[1])]"/> But this produces no output at all. I'm sure what I'm missing is blatently obvious... :-/ I'm using Sablotron 1.0, if that makes any difference. Thanks in advance, Laura. XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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