Subject: [xsl] generate XHTML header without causing xmlns attributes in e.g. <table>? From: Flemming Jønsson <flj@xxxxxxxxxxxxx> Date: Fri, 17 Oct 2003 08:58:01 +0200 |
I need to generate valid XHTML 1 strict from my XSL stylesheet My stylesheet starts with: <xsl:stylesheet version="1.0" xmlns="http://www.w3.org/1999/xhtml" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output method="xml" encoding="ISO-8859-1" doctype-public="-//W3C//DTD XHTML 1.0 Strict//EN" doctype-system="DTD/xhtml1-strict.dtd" /> When I generate my XHTML document using Xalan-J, I get these headers in the XHTML file <?xml version="1.0" encoding="ISO-8859-1"?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "DTD/xhtml1-strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> Which is exactly what I want. However, my tables cannot validate using w3c's validator, since they get an empty attribute with the name xmlns, like this: <table xmlns="" id="y" class="z"> Also the XHTML tags inside the table (not td/tr but all others) also get the xmlns attribute which has no value and they also get an xmlns:fo attribute like this: <br xmlns="" xmlns:fo="http://www.w3.org/1999/XSL/Format" /> How can I generate valid XHTML1 without having those xmlns attributes inserted in table and <br>? If they must be there, how can I control their value? Regards, Flemming Joensson XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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