Re: [xsl] My Intent: Template to generate RTF

Subject: Re: [xsl] My Intent: Template to generate RTF
From: Wendell Piez <wapiez@xxxxxxxxxxxxxxxx>
Date: Fri, 17 Oct 2003 15:28:03 -0400
Karl,

I might add,

At 02:52 PM 10/17/2003, I wrote:
Anyways, this is what I ended up with for a variable declaration:
<xsl:variable name="xmTmplt"
select="$DOC_TEMPLATE_XML//DOC[@id=ancestor-or-self::*[count(current()/ances
tor-or-self::*)-1]/@id]"/>

Its a bit messy, but it works (is this common?  maybe this isn't messy, but
is the most *complex* xpath expression I've written so far).

I've written much worse. So common ... no ... unheard-of ... not at all.

On the other hand, the expression above could be tightened to


$DOC_TEMPLATE_XML//DOC[@id=ancestor::*[last() - 1]/@id]

or even

$DOC_TEMPLATE_XML//DOC[@id=ancestor::*/@id]

if the ancestor you are interested in is the only ancestor with an @id (ancestor::*/@id collects @id attributes on all ancestors).

Cheers,
Wendell


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