Subject: RE: [xsl] xsl variable - issue From: "Michael Kay" <mhk@xxxxxxxxx> Date: Fri, 24 Oct 2003 17:57:55 +0100 |
The code you've shown us looks fine. This probably means the bug is in the code you haven't shown us. Michael Kay > -----Original Message----- > From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx > [mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx] On Behalf Of Mark Ivs > Sent: 24 October 2003 16:57 > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > Subject: [xsl] xsl variable - issue > > > Hello, > Please take a look at the XML and XSL files. I have > variable called contentsVar which contains a node set. > For some reason, the 'if' statement is failing though > the XML says isvisible = true. Not sure what I am > doing wrong. > Any help will be appreciated. > > Thanks. > > XML: > > <root> > <book> > <contents isvisible="true"> > <chap> > <chap> > </contents> > </book> > </root> > > XSL: > > <xsl:template match="book"> > <xsl:variable name="contentsVar" select="contents"/> > . > . > . > <xsl:if test="$contentsVar/@isvisible = 'true'"> > do something... > </xsl:if> > </xsl:template> > > __________________________________ > Do you Yahoo!? > The New Yahoo! Shopping - with improved product search http://shopping.yahoo.com XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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