Subject: RE: [xsl] Making XPath expressions out of variables From: "Michael Kay" <mhk@xxxxxxxxx> Date: Wed, 29 Oct 2003 16:03:42 -0000 |
You either need to generate the whole stylesheet before you start, or you need to make extensive use of the xx:evaluate() extension function (and an XSLT processor that supports it). Michael Kay > -----Original Message----- > From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx > [mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx] On Behalf Of > Richard Lewis > Sent: 29 October 2003 13:09 > To: XSL-List@xxxxxxxxxxxxxxxxxxxxxx > Subject: [xsl] Making XPath expressions out of variables > > > This is a theoretical bit of XSL code which I need a > practical version of: > > All the variables are passed as parameters to the stylesheet. > > <xsl:for-each select="//$record-type"> > <xsl:sort select="$sort-by" order="$sort-order" /> > <xsl:if test="$lh-operator $operand $rh-operator"> > <tr> > <xsl:for-each select="*"> > <td><xsl:value-of select="." /></td> > </xsl:for-each> > </tr> > </xsl:if> > </xsl:for-each> > > Any ideas? Is it possible? Or do I need to use this basic > construct multiple > times using <xsl:if> for each variable and the correct names > of nodes and > operands. (The number of permutations is massive!) > > Cheers, > Richard > ------------------------------------------------------------- > This is question I was going to ask (it might make things clearer): > > Is there a way of selecting nodes which have the name > $some-variable using an > XPath expression? > > e.g. <xsl:for-each select="//$some-variable"> > > would, in theory (though not in practice - I've tried it!), > select all the > nodes whose name is equal to whatever the value of $some-variable is. > ------------------------------------------------------------- > > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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