[xsl] Re: Converting specific child elements into attriutes of parent

Subject: [xsl] Re: Converting specific child elements into attriutes of parent
From: "Dimitre Novatchev" <dnovatchev@xxxxxxxxx>
Date: Thu, 30 Oct 2003 10:01:01 +0100
> I have been trying to convert specific child elements into attributes of
the
> parent node.  I looked through archive, there was a topic of converting
all
> children to attributes of the root.  I followed the same thing and tried
to
> convert a specific child element, but i am getting following error.
> elmToAtt.xsl; Line 18; Column -1; name() has an illegal attribute: {1}
> I would like to copy the xml document and convert only specific elements
> into attributes.
> I am not able to make out why this error is, but to no avail.  Hoping that
> anybody in the list would help to resolve .

The specific error can be corrected by using AVT like this:

name="{name()}"

Here's a transformation, which converts any element, whose name is in a list
of names, to an identically named attribute of its parent:


<xsl:stylesheet version="1.0"
 xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
 xmlns:my="my:my"
 exclude-result-prefixes="my"
 >

 <xsl:output omit-xml-declaration="yes" indent="yes"/>
 <xsl:strip-space elements="*"/>

 <my:elNames>
   <name>id</name>
 </my:elNames>

 <xsl:variable name="elNames"
      select="document('')/*/my:elNames/name"/>

  <xsl:template match="@* | node()">
    <xsl:copy>
      <xsl:apply-templates select="@* | node()"/>
    </xsl:copy>
  </xsl:template>

  <xsl:template match="*">
    <xsl:choose>
      <xsl:when test="not(name() = $elNames)">
        <xsl:copy>
          <xsl:copy-of select="@*"/>
          <xsl:apply-templates select="*[name() = $elNames]"/>
          <xsl:apply-templates/>
        </xsl:copy>
      </xsl:when>
      <xsl:otherwise>
        <xsl:attribute name="{name()}">
          <xsl:value-of select="."/>
        </xsl:attribute>
      </xsl:otherwise>
    </xsl:choose>
  </xsl:template>

  <xsl:template match="value">
    <xsl:value-of select="."/>
  </xsl:template>
</xsl:stylesheet>

When this transformation is applied on your original source.xml:

<customerList>
  <customer>
    <field>
      <id>customerId</id>
      <value>cust1</value>
    </field>
    <field>
      <id>customerName</id>
      <value>Customer  1</value>
    </field>
    <fieldGroup>
      <id>homeAddress</id>
      <fieldList>
        <field>
          <id>street</id>
          <value>98th  Street </value>
        </field>
        <field>
          <id>city</id>
          <value>Chicago</value>
        </field>
      </fieldList>
    </fieldGroup>
    <fieldGroup>
      <id>companyAddress</id>
      <fieldList>
        <field>
          <id>street</id>
          <value>128th  Street</value>
        </field>
        <field>
          <id>city</id>
          <value>Chicago</value>
        </field>
      </fieldList>
    </fieldGroup>
  </customer>
</customerList>

the wanted result is produced:

<customerList>
   <customer>
      <field id="customerId">cust1</field>
      <field id="customerName">Customer  1</field>
      <fieldGroup id="homeAddress">
         <fieldList>
            <field id="street">98th  Street </field>
            <field id="city">Chicago</field>
         </fieldList>
      </fieldGroup>
      <fieldGroup id="companyAddress">
         <fieldList>
            <field id="street">128th  Street</field>
            <field id="city">Chicago</field>
         </fieldList>
      </fieldGroup>
   </customer>
</customerList>


Hope this helped.


=====
Cheers,

Dimitre Novatchev.
http://fxsl.sourceforge.net/ -- the home of FXSL




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