[xsl] html table of sorted element names

[Saverio Perugini <sperugin@xxxxxxxxxxxxxxxx>]

Hello,

I'd like to produce a 4 column HTML table where the
text contained in each <td> element is alphabetically
sorted from cell (1,1) to cell (n,4),
where n is the required number of rows.

The following is an attempt:

<xsl:template match="/db">
   <xsl:if test="*[some condition]">
      <xsl:variable name="sortedelements">
         <xsl:for-each select="*">
            <xsl:sort data-type="text" select="name()"/>
            <xsl:copy-of select="."/>
         </xsl:for-each>
      </xsl:variable>

      <xsl:variable name="sortedelementsNodeSet"
                    select="exsl:node-set($sortedelements)/*"/>
      <table>
         <xsl:for-each select="$sortedelementsNodeSet[position() mod 4 = 1]">
            <tr>
               <xsl:for-each select=".|following-sibling::node()[position() &lt; 4]">
                   <td><xsl:value-of select="name()"/></td>
               </xsl:for-each>
            </tr>
         </xsl:for-each>
      </table>
   </xsl:if>
</xsl:template>

While this produces a table, not all rows contain four columns, and even
worse, the text contained in the <td>'s is not sorted across all <td>'s.

I am using libxslt, which supports the node-set() exslt function.
Does anyone see what is going wrong here?

Thanks,
Saverio

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