Subject: [xsl] Re: Excluding one particular attribute(namespace) when copying elements From: "Dimitre Novatchev" <dnovatchev@xxxxxxxxx> Date: Fri, 31 Oct 2003 22:25:15 +0100 |
> I need to copy different element to output. For all > the elements I need to exclude the namespace attribute > when i use "xsl:copy-of" or "xsl:copy". It seems > difficult to specify this in XSLT. Any comment would > be appreciated! Use something like this: <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output omit-xml-declaration="yes"/> <xsl:template match="t"> <xsl:element name="{name()}"> <xsl:copy-of select="namespace::*[not(. = 'b')]"/> <xsl:copy-of select="@* | node()"/> </xsl:element> </xsl:template> </xsl:stylesheet> When this transformation is applied on the following source.xml: <t xmlns:a="a" xmlns:b="b"/> the result is: <t xmlns:a="a"/> so the namespace "b" has been excluded. Hope this helped. ===== Cheers, Dimitre Novatchev. http://fxsl.sourceforge.net/ -- the home of FXSL XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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