Re: [xsl] ?Formating Issue?

[David Carlisle <davidc@xxxxxxxxx>]

<xsl:for-each select="livelink">

why the for-each? You only have one livelink element.
probably you want something like


<xsl:template match="livelink">
<table>
<tr>
<td>You are here >>></td>
<xsl:for-each select="location">
<td><xsl:value-of select="."/></td>
</xsl:for-each>
</tr>
</table>
</xsl:template>

although that doesn't do anything with your  path='..\' attribute.

David


-- 
http://www.dcarlisle.demon.co.uk/matthew

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