Subject: [xsl] RE: XSL-List Digest V4 #1774 From: constantin.vasiliu@xxxxxxxxxxxxxx Date: Thu, 6 Nov 2003 17:21:49 -0800 |
> Try to restructure it so you select the subset using xsl:for-each. > > Instead of > > <xsl:for-each select="x"> > <xsl:if test="c"> > <tr> > > do > > <xsl:for-each select="x[c]"> > <tr> Excellent advice! Now that you mentioned it, it really looks simple! :) But that's the role of an expert--to make it look simple. Got it working. It wasn't as simple as the above because the XML document had a recursive structure, thus I had to decide when to choose the node subset on other checks (to avoid selecting a null node-set and get no output). However, pointing me in the right direction made the whole difference. > > > <xsl:value-of select="name(element[.//*[conditions]][1])"/> > > > > Can you explain more on this? Should "element" stay as such > > or be replaced with the real name of the element I'm looking > > for (which turns out to be "Sequence"). > > This was intended as pseudo-code. Substitute the right things for > "element" and "conditions". I didn't need to do this any more. Solving the first problem gave a free solution for this one too. Once I got the correct subset, I could make the decision to output what I wanted based on the position info. > > Also, "conditions" > > need to contain an "xsl:for-each". Is that possible? > > No, it's not possible, but are you really sure it is necessary? I guess not, since I could solve it another way. Many thanks, Michael, your help was very valuable! Constantin Vasiliu XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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