| Subject: Re: [xsl] generating xml from xml From: David Carlisle <davidc@xxxxxxxxx> Date: Mon, 10 Nov 2003 16:00:32 GMT | 
I think you just want the indentity transformation (copied from the xslt
spec)
 with one extra template
<xsl:template match="Trade/*">
 <xsl:element name="{/Data/Fields/_[@id=name(current())]/@fn}">
  <xsl:apply-templates/>
 </xsl:element>
</xsl:template>
> and my limitation is, the parser I can use should be MSXML3.0 or less. 
the above will work with any xslt system, which includes msxml3, clearly
msxml previous to version 3 won't work as it doesn't implement xslt at
all.
David
-- 
http://www.dcarlisle.demon.co.uk/matthew
________________________________________________________________________
This e-mail has been scanned for all viruses by Star Internet. The
service is powered by MessageLabs. For more information on a proactive
anti-virus service working around the clock, around the globe, visit:
http://www.star.net.uk
________________________________________________________________________
 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
| Current Thread | 
|---|
| 
 | 
| <- Previous | Index | Next -> | 
|---|---|---|
| [xsl] generating xml from xml, Murali Korrapati | Thread | Re: [xsl] generating xml from xml, Wendell Piez | 
| Re: [xsl] Lookup without document(', Wendell Piez | Date | Re: [xsl] Problem with Muenchian gr, Wendell Piez | 
| Month |