Subject: Re: [xsl] generating xml from xml From: David Carlisle <davidc@xxxxxxxxx> Date: Mon, 10 Nov 2003 16:00:32 GMT |
I think you just want the indentity transformation (copied from the xslt spec) with one extra template <xsl:template match="Trade/*"> <xsl:element name="{/Data/Fields/_[@id=name(current())]/@fn}"> <xsl:apply-templates/> </xsl:element> </xsl:template> > and my limitation is, the parser I can use should be MSXML3.0 or less. the above will work with any xslt system, which includes msxml3, clearly msxml previous to version 3 won't work as it doesn't implement xslt at all. David -- http://www.dcarlisle.demon.co.uk/matthew ________________________________________________________________________ This e-mail has been scanned for all viruses by Star Internet. The service is powered by MessageLabs. For more information on a proactive anti-virus service working around the clock, around the globe, visit: http://www.star.net.uk ________________________________________________________________________ XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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