RE: [xsl] access preceding record

[rolf@xxxxxxxxx]

I couldn't bring this to work, Jarno.

Your snippet says: "any time you see a record, copy it to output including
descendents. Add an element stop and set its value to the value of the
preceding record/start element.". Right?

But it won't do that.

And I do not know where to start and how to debug this.

However, the missing point in my thought was "preceding::record[1]" or
"../preceding-sibling::record[1]" in order to reference the preceding
record.

Rolf

> Hi,
>
>> A sortet set of records - each containing one value -
>> should be transformed into the same number of records
>> with two values where the second value is that from the
>> preceding record.
>
> [snip]
>
>> Can you think of a transformation?
>> In which direction I have to think?
>
>   <xsl:template match="record">
>     <xsl:copy>
>       <xsl:apply-templates select="*"/>
>       <stop>
>         <xsl:value-of select="preceding::record[1]/start"/>
>       </stop>
>     </xsl:copy>
>   </xsl:template>
>   <xsl:template match="@* | node()">
>     <xsl:copy>
>       <xsl:apply-templates select="@* | node()"/>
>     </xsl:copy>
>   </xsl:template>
>
> Cheers,
>
> Jarno - Revolution By Night: Faithless (by Ronan Harris)
>
>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
>
>


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