Re: [xsl] position() of parent node

["J.Pietschmann" <j3322ptm@xxxxxxxx>]

Robert Ogden wrote:
> 		<xsl:for-each select="imageLink">
> 			<xsl:if test="chapter[position() != 21]">
...
> What I am getting at, is that I want to output all text links (easy
> enough), and all images for chapters unless the chapter is 21 (which
> happens also to be last, which I tried <xsl:if test="chapter[position()
> != last()]">)

Well, the <chapter> is, as you noted, the parent of imageLink,
therefore the XPath "chapter[position() != 21]" inside the
for-each wont select anything (independently of the predicate,
because there is no <chapter there).

You can try to count the previous siblings of the chapter. Of
course, you'll have to navigate to the parent first:
 <xsl:if test="parent::chapter[count(previous-sibling::chapter)=21]">
or if you want the last (no following sibling chapter):
 <xsl:if test="parent::chapter[not(following-sibling::chapter)]">

J.Pietschmann



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