Subject: Re: [xsl] Converting Duration From: tim@xxxxxxxxxxxx Date: Fri, 21 Nov 2003 12:48:04 -0800 |
On Fri, Nov 21, 2003 at 07:43:37PM +0100, J.Pietschmann wrote: > kakridge@xxxxxxxxxxxxx wrote: > > If I have varying durations within an element, such as this: > > > > <Durations> > > <Duration>PT8H</Duration> > > <Duration>PT8H15M</Duration> > > <Duration>PT12H10M</Duration> > > </Durations> > > > > how can I scan through and strip out the letters? > > Stripping letters can be achieve by translating them to nothing: > <xsl:template match="Duration"> > <xsl:value-of select="translate(.,'PTHSM','')"/> > </xsl:template> > Of course, you can delete 'ABCD...' or whatever. > > I'm not sure what stripping the letters gives you, nor what you mean > by "scan through". For more help, you'll have to supply samples of the > expected output. > > J.Pietschmann > > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list > Some samples would help responses. However, you might want to check out some of the date-time functions in EXSLT. See http://www.exslt.org for more info. I know there are some functions to handle durations, so maybe you can find an example or something there. Best of luck, Tim -- /** * Tim Meals * Applications Developer * * @email: tmeals@xxxxxxxxxxxx */ XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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