[xsl] crossreferencing any element

Hiya,  using either xslt1 or xslt2, I want to match *any* element
that has a @corresp attribute, and for each whitespace separated
idref contained within, produce a link to this id.  I don't know
what elements will have @id or @corresp, and they will all also
have templates doing other things to them. I think xslt2 tokenize()
is an easy way to get at the idrefs, and copying any instance of
@id is fairly straightforward.  But I get warnings of ambiguous
matches each time I try to match an element (for example para) and
also have a general match for it to create the cross referencing
links.

Let's say I have an input of something structurally akin to:
--------
<document>
<para id="a1" corresp="a2 a4"> This is a test</para>
<para id="a2" corresp="a1"> This paragraph refers to a1</para>
<para id="a3"> This paragraph does not refer to a1</para>
<para id="a4" corresp="a1 q54"> This paragraph refers to a1 and
q54</para>
<para id="a5" corresp="a6"> This paragraph refers to a6</para>
<para id="a6" corresp="a1 a5"> This paragraph refers to a1 and a5</para>
<para id="a7">
This is a longer paragraph that has a
<ab id="q54" corresp="a4">span</ab> that
refers back to a4.
</para>
</document>
--------

And want a fairly straightforward transformation into:
--------
<html>
<body>
<p id="a1"> <a href="#a2">[xref]</a> <a href="#a4">[xref]</a>This is a
test</p>
<p id="a2"> <a href="#a1">[xref]</a> This paragraph refers to a1</p>
<p id="a3"> This paragraph does not refer to a1</p>
<p id="a4"> <a href="#a1">[xref]</a> <a href="#q54">[xref]</a> This
paragraph refers to a1 and q54</p>
<p id="a5"> <a href="#a6">[xref]</a> This paragraph refers to a6</p>
<p id="a6"> <a href="#a1">[xref]</a> <a href="#a5">[xref]</a> This
paragraph refers to a1 and a5</p>
<p id="a7">
This is a longer paragraph that has a
<span class="ab" id="q54"><a href="#a4">[xref]</a>span</span> that
refers back to a4.
</p>
</body>
</html>
--------

Suggestions?

-James

---
Dr James Cummings, Oxford Text Archive, James.Cummings@xxxxxxxxxxxxxx

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