Re: [xsl] crossreferencing any element

[David Carlisle <davidc@xxxxxxxxx>]

I'm assuming that I should then do
something like:

something like but...


Then you can't quite do

<xsl:template match="node()">
<xsl:copy>
 <xsl:copy-of select="@id"/>
 <xsl:apply-templates select="id(@corresp)" mode="link"/>
 <xsl:apply-templates select="node()|@*"/>
</xsl:copy>

as applying templates to @* will copy the attribute node and you can't
add attributes after you have added child nodes (your link text) so you
need to do them first


<xsl:template match="node()">
<xsl:copy>
 <xsl:copy-of select="@*[not(name()='corresp']"/>
 <xsl:apply-templates select="id(@corresp)" mode="link"/>
 <xsl:apply-templates select="node()"/>
</xsl:copy>




-- 
http://www.dcarlisle.demon.co.uk/matthew

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